During daylight hours my RST would be 559, or even lower.
Please notice that a power of 500 mW is only four S-points weaker than 100 Watts.
See the PA1B QRPp page.
D and E layer
The radio wave is not attenuated when it is reflected by the E-layer. (Total reflection) But during daytime the signal is attenuated by the D-layer, when it passes through the D-layer.
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| During daylight hours, the signals are attenuated by the D-layer, which is absorbing |
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| The E-layer reflects the signal without attenuation |
When the D-layer disappears, there is no attenuation in the radio path. The signal is reflected by the E-layer without attenuation. The attenuation of this sky wave is (only) 6 dB for a doubling of the distance. So the signal will be very strong.
At first, I did not realize, that my own QRPp signal, could also be an earsplitting 599, until I got genuine report from Italy, that my signal was S9, while using just 500 mW.
How low can you go
I was wondering, what the lowest possible power would be, if I would reduce my power in that situation with this excellent propagation.If I reduced my power, so my RST would be 559, the difference is 4 S-point. This is a reduction in power of 4 x 6 dB = 24 dB which is 4 x 4 x 4 x 4 = 256.
So I could reduce the the power from 500 mW to about 2 milliwatts.
From 2001 on, I made many CW contest QSO's over more than 1000 Miles with 2.5 mW and 5 mW,
using PA1B homebrew attenuators.
I discovered that the frequency must be absolutely clear, when you use very low power.


